Count word frequency in a sentence in python

Question

Anubhav Kumar · Answer

Problem Statement
Given a sentence like:
sentence = "hello world hello war is upcoming"
You need to return:
{'hello': 2, 'world': 1, 'war': 1, 'is': 1, 'upcoming': 1}
Approach
Split the sentence into words.Use a dictionary to count the number of times each word occurs.Optionally, convert all words to lowercase for case-insensitive calculations.
Solution in Python
def count_word_frequency(sentence):
    # Step 1: Convert to lowercase to avoid case mismatches
    sentence = sentence.lower()
    # Step 2: Split sentence into words
    words = sentence.split()
    # Step 3: Create an empty dictionary to hold word counts
    word_count = {}
    # Step 4: Count each word
    for word in words:
        if word in word_count:
            word_count[word] += 1  # Increment count if word already exists
        else:
            word_count[word] = 1   # Initialize count if word appears for the first time
    return word_count
# Example usage:
sentence = "Hello world hello"
result = count_word_frequency(sentence)
print(result)
Explanation
sentence.lower(): Ensures "Hello" and "hello" are treated as the same.sentence.split(): Splits on whitespace by default.The dictionary word_count stores each word as a key and its count as a value.
Output:
{'hello': 2, 'world': 1, 'war': 1, 'is': 1, 'upcoming': 1}
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Count word frequency in a sentence in python

Anubhav Kumar

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